Without an external gravity field there is no gravitational interaction with the atom
So what could be the effect of placing the atom into a gravity field.
When looking to the atom with his electron cloud (wave function) surrounding the proton. One can
imagine that the cloud itself has a negative charge (field-strength) caused by the negativity of the
electron. This charge is in equilibrium with the charge of the core ( the proton). With this in mind we
assume this atom is somewhere on Earth’s surface undergoing its gravity force. The external gravity
force is influencing the electron field of the atom. The electron cloud responds. And the net charge is
divided on the cloud to create a counter charge equal to the size of the gravity deviation. Result is
that the electron cloud is directed like an polar magnet.
With influencing the “locally” charge of the electron cloud, the equilibrium in (Coulomb force and
centripetal force) energy between proton and electron is disturbed( See Tie-graph). To create a new
equilibrium ( for Fc=Fcp) there is an interaction between the proton charge and the electron charge.
To achieve this new equilibrium the positive charge of the proton can move its center towards the side of
the atom in which the Coulomb force increases.
The influenced locally charge causes the nucleus (proton) to move its centre and influences the cloud function in a way that opposite charges in relation to the gravity field strength occur. The new equilibrium between the Coulomb force and the Centripetal force can be described (only for this simplified system) with help of Kepler’s Law of Planetary Motion.